the strength of 10^-2 m na2co3 we are issue in this question in my exam

the strength of 10^-2 m na2co3 we are issue in this question in my exam the strength of 10^-2 m na2co3 we are issue in this question in my exam the strength of 10^-2 m na2co3 we are issue in this question in my exam the strength of 10^-2 m na2co3 we are issue in this question in my exam

To calculate the strength of a 10−2 M Na2CO310^{-2} \, \text{M} \, \text{Na}_2\text{CO}_3 solution, you need to determine its mass per liter (usually expressed in grams per liter, g/L\text{g/L}).

Steps to Calculate Strength:

  1. Molarity Formula:Strength (g/L)=Molarity (M)×Molar Mass (g/mol)\text{Strength (g/L)} = \text{Molarity (M)} \times \text{Molar Mass (g/mol)}
  2. Molar Mass of Na2CO3\text{Na}_2\text{CO}_3:
    • Sodium (Na\text{Na}): 23 g/mol23 \, \text{g/mol}, so 2×23=46 g/mol2 \times 23 = 46 \, \text{g/mol}
    • Carbon (C\text{C}): 12 g/mol12 \, \text{g/mol}
    • Oxygen (O\text{O}): 16 g/mol16 \, \text{g/mol}, so 3×16=48 g/mol3 \times 16 = 48 \, \text{g/mol}
    • Total molar mass of Na2CO3\text{Na}_2\text{CO}_3: 46+12+48=106 g/mol46 + 12 + 48 = 106 \, \text{g/mol}
  3. Substitute Values:Strength=10−2 M×106 g/mol=1.06 g/L\text{Strength} = 10^{-2} \, \text{M} \times 106 \, \text{g/mol} = 1.06 \, \text{g/L}

Final Answer:

The strength of a 10−2 M Na2CO310^{-2} \, \text{M} \, \text{Na}_2\text{CO}_3 solution is 1.06 g/L.

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the strength of 10^-2 m na2co3 we are issue in this question in my exam

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